Find the equation of the line that contains the point ( -3, -1 ) and is parallel to the line 6x+5y=11 write the equation in slope intercept form

Answer:To find the equation of the line, you must first of all find the slope in the given equation,how do you do that? You just need to make y the subject of the formula and then compare the resulting equation to y = mx + c, knowing fully well that m represent the slope.i.e from the equation 5y = 11 - 6x                                       y = 11/5 - 6x/5i,e the slope is -6/5Note: for two lines to be parallel, they must have the same slopei.e m1 = m2using the formula y - y1 = m ( x - x 1) to find the equation of the lineit implies : y - (-1) = -6/5 ( x - {-3})                  y + 1 = -6/5 ( x +3)multiply through by 55 ( y+1) = -6 ( x +3)5y +5 = -6x - 18       5y = -6x -18-5        5y = -6x -23       To write it in slope intercept form, divide through by 5         y = -6x/5  - 23/5Step-by-step explanation: